Suppose the temperature outside is dropping at a constant rate. At noon , the temperature is 70 degrees f and it drops to 58 degrees f at 5:00 P.M. How much did the temperature change each hour?

User Icon for Damon Damon answered
16 years ago

70 - 58 = 12 degrees in five hours

12/5 = 2.4 degrees per hour drop or -2.4 degrees per hour

User Icon for JO JO answered
16 years ago

Evaluate. | –48 |

User Icon for Damon Damon answered
16 years ago

+48

User Icon for Jackie Jackie answered
13 years ago

During a six hour period, the temperture dropped 18degrees F. Find the average hourly change in the temperature.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find out how much the temperature changed each hour, we need to calculate the temperature change per hour. We can do this by finding the difference between the initial temperature and the final temperature, and then dividing it by the number of hours.

In this case, the initial temperature at noon is 70 degrees Fahrenheit and the final temperature at 5:00 P.M. is 58 degrees Fahrenheit. The time interval between noon and 5:00 P.M. is 5 hours.

So, to find the temperature change per hour, we can use the formula:

Temperature change per hour = (Final temperature - Initial temperature) / Number of hours

Temperature change per hour = (58°F - 70°F) / 5 hours

Temperature change per hour = -12°F / 5 hours

Now we can simplify this:

Temperature change per hour = -2.4°F / hour

Therefore, the temperature is dropping by approximately 2.4 degrees Fahrenheit per hour.