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Question

2. For what values of x dies the graph of f(x)=2x^3-3x^2-6x+87 have a horizontal tangent?

My answer:

(1.6,77.9)

(-0.62, 89.1)
10 years ago

Answers

Reiny
dy/dx = 6x^2 - 6x - 6
= 0 for a horizontal slope
x^2 - x - 1 = 0
x = (1 ± √5)/2
= appr 1.618 or -.618

you are correct, but all it asked for is the values of x

(did you know that the first answer x = 1.618.. is the "golden ratio " ? )
10 years ago

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