Asked by jhon
Fe + O2--->Fe2O3
How many grams of iron are required to convert 80 mL of oxygen at STP?
How many grams of iron are required to convert 80 mL of oxygen at STP?
Answers
Answered by
DrBob222
4Fe + 3O2 --> 2Fe2O3
mols O2 = 80 mL x (1 mol/22,400 mL) = ?
Using the coefficients in the balanced equation, convert mols O2 to mols Fe.
Then convert mols Fe to grams. g = mols x atomic mass Fe.
mols O2 = 80 mL x (1 mol/22,400 mL) = ?
Using the coefficients in the balanced equation, convert mols O2 to mols Fe.
Then convert mols Fe to grams. g = mols x atomic mass Fe.
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