Asked by Trish Goal
Given the functions
f(x)=x+5/3 and g(x)=1/f^-1(x)+1, find the value of g(3).
The first step would first be to find the inverse of x+1, the denominator of the fraction. I think the inverse would be 1-x. And now we have 1/1-x so we can just plu in 3. Right?
f(x)=x+5/3 and g(x)=1/f^-1(x)+1, find the value of g(3).
The first step would first be to find the inverse of x+1, the denominator of the fraction. I think the inverse would be 1-x. And now we have 1/1-x so we can just plu in 3. Right?
Answers
Answered by
Reiny
I have a feeling you meant f(x) = (x+5)/3
or is it the way you typed it ?
confirm please
or is it the way you typed it ?
confirm please
Answered by
Trish Goal
Yes it is (x+5)/3 thank you for correcting me.
Answered by
Trish Goal
Given the functions
f(x)=(x+5)/3 and g(x)=1/f^-1(x)+1, find the value of g(3).
The first step would first be to find the inverse of x+1, the denominator of the fraction. I think the inverse would be 1-x. And now we have 1/1-x so we can just plu in 3. Right?
f(x)=(x+5)/3 and g(x)=1/f^-1(x)+1, find the value of g(3).
The first step would first be to find the inverse of x+1, the denominator of the fraction. I think the inverse would be 1-x. And now we have 1/1-x so we can just plu in 3. Right?
Answered by
Steve
f(x) = (x+5)/3
f^-1(x) = 3x-5
g(x) = 1/(f^-1(x)+1) = 1/(3x-4)
g(3) = 1/5
Of course, you might also have meant just what you typed, in which case
g(x) = 1/f^-1(x) + 1 = 1/(3x-5) + 1 = (3x-4)/(3x-5)
and so g(3) would be 5/4
f^-1(x) = 3x-5
g(x) = 1/(f^-1(x)+1) = 1/(3x-4)
g(3) = 1/5
Of course, you might also have meant just what you typed, in which case
g(x) = 1/f^-1(x) + 1 = 1/(3x-5) + 1 = (3x-4)/(3x-5)
and so g(3) would be 5/4
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.