f^-1(x) = (x-5)/4
So,
f^-1(9) = 1
f^-1(1) = -1
So, no, the answer would be -1.
Suppose that f(x)=4x+5. What is
f^-1(f^-(9))?
I am pretty sure we can plug in 9 for f(x) which gives us the value of 1. But then we have one more f^-1 but the inverse of 1 is -1. So would the answer be one?
1 answer