Question
a 10.0m long bar is attached by a frictionless hing to a wall and held horizontally by a rope that makes an angle of 53 deg with the bar the bar is uniform and weights 39.9 N. how far from the hinge should a 10.0kg mass be suspended for the tension T in the rope to be 125 N
Answers
12.4
a uniform beam LM has a weight of 60N and is 5 M long. it rest on a pivot at P. PM=1.6m. A 80N weight hangs from L.A vertical rope attached midway between P and M prevents the beam from rotating. calculate the tension T in the rope?
It's not 12.4, you have to find the perpendicular distance from T and the hinge. Also the bar is only 10 m so an answer longer than that makes no sense
Forfit to add the answer is 8.15m
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