Asked by anisa
Erica throws a ball out of a window with a horizontal speed of 3.8m/s. If the ball hits the ground 15m away, how high up is the window?
My work:
X-direction
v1x=3.8m/s
v2x=3.8m/s
a=0m/s2
d=15m
y-direction
I don't know how to find the initial and final velocity.
a=-9.8m/s2
I found time by using the equation:
t=d/v
t=15/3.8
t=3.95
it took the ball 3.95 seconds to reach the ground. since I have time for both y and x direction, i thought it would be easier for me to find distance but i don't know how to find the initial and final velocity. if the initial velocity of y direction is 0m/s, how do i find the final velocity
My work:
X-direction
v1x=3.8m/s
v2x=3.8m/s
a=0m/s2
d=15m
y-direction
I don't know how to find the initial and final velocity.
a=-9.8m/s2
I found time by using the equation:
t=d/v
t=15/3.8
t=3.95
it took the ball 3.95 seconds to reach the ground. since I have time for both y and x direction, i thought it would be easier for me to find distance but i don't know how to find the initial and final velocity. if the initial velocity of y direction is 0m/s, how do i find the final velocity
Answers
Answered by
bobpursley
height=1/2 g t^2
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