Question

if

n+5-n+3 over n-3-n-5=16

what is the value of n

this is an SAT question and i just cant seem to figure it out..even with pluggin in the numbers it never = 16...so help pls..what is the quickest way in solving this for the SAt's

Answer 1

The n's cancel out in the numerator AND denominator, and you are left with
8/(-8) = -1 = 16, which is of course not true, and cannot be solved for n. Are you sure you copied the problem correctly?

Answer 2

yeah n+5 should be over n-3 and n+3 should be over n-5 and your subtracting this frm eachother to equal 16

the possible answers are
-4
-2
2
4
6

Answer 3

If you mean
[(n+5)/(n-3)] - [(n+3)/(n-5)] = 16
First rewrite the left with a common denominator, (n-3)(n-5). You get
[(n^2-25) - (n^2-9)]/[(n-3)((n-5)]= 16
-16/[(n-3)(n-5)]= 16
(n-3)(n-5) = -1
n = 4

That is completely different from what you typed at first.

Answer 4

im soo sry...but that was it..thanxs soo much :)