Question

You wish to make a 0.195 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?
mL1 x M1 = mL2 x M2
mL1 x 6.00 = 50.0 mL x 0.195
So you want mL1 of the 6.00 M solution to be placed in a container and add water to a total of 50.0 mL.
1.625ml

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