Question
Hi I see another student actually posted this question... but got no answer... is someone able to look at it? see below -
a bullet is fired at and passes a piece of target paper suspended by a massless string. The bullet has a mass of m, a speed v before the collision with the target, and a speed (0.466)v after passing through the target. The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction [(0.453)KEb BC] of the kinetic energy of the bullet before the collision. Determine the mass M of the target and the speed V of the target the instant after the collision in terms of mass m of the bullet and speed v of the bullet before the collision. Express answer t0 3 decimals.
a bullet is fired at and passes a piece of target paper suspended by a massless string. The bullet has a mass of m, a speed v before the collision with the target, and a speed (0.466)v after passing through the target. The collision is inelastic and during the collision, the amount of energy lost is equal to a fraction [(0.453)KEb BC] of the kinetic energy of the bullet before the collision. Determine the mass M of the target and the speed V of the target the instant after the collision in terms of mass m of the bullet and speed v of the bullet before the collision. Express answer t0 3 decimals.
Answers
bobpursley
Good lord, talk about busy work. I think I would look for another instructor, this one likes to not teach, but demonstrate how clever they are.
First, you know the speed of the bullet the bullet in terms of initial v.
you also know Ke as a fraction..
KE: finalKE+energy lost=inital KE
1/2 m (.466v)^2+.453*1/2 m v^2=1/2mv^2
somehow, I see inconsistency here.
First, you know the speed of the bullet the bullet in terms of initial v.
you also know Ke as a fraction..
KE: finalKE+energy lost=inital KE
1/2 m (.466v)^2+.453*1/2 m v^2=1/2mv^2
somehow, I see inconsistency here.
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