Question

a warehouse employee is pushing a 38 kg desk across a floor at a constant speed of 0.4 m/s. How much work must the employee do on the desk to change the speed of 1.5m/s?
According to work energy theorem workdone=change in kinetic energy of the body.W=1/2M(V2^2-V1^2)=1/2(38)(1.5^2-0.4^2)=39.71Joules

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