1125 = 250 * 0.45 * (55 - t)
solve for t
1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).
What was the temperature of the iron before it was heated?
1 answer
What was the temperature of the iron before it was heated?
1 answer