Asked by Trish Goal

For real numbers a and b, define a%b=sqrt(a^2+b^2). What is the value of (5%12)%((-12)%(-5))?

The percentage is just a random sign the problem had a diamond instead, I just couldn't find any other symbol.Thank you!
Answered by Steve
a%b = √(a^2+b^2)

so, just plug in your numbers:

5%12 = (-5)%(-12) = 13

so, you have

(13)%(13) = 13√2

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