Asked by Alex
Using an appropriate linear approximation approximate 26.9^(4/3).
Answers
Answered by
Steve
27^(4/3) = 81
y = x^(4/3)
dy = (4/3)x^(1/3) dx
so, if dx = -0.1
dy = (4/3)(3)(-0.1) = -0.4
So, 26.9^(4/3) ≈ 80.6
In fact 26.9^(4/3) = 80.6002
pretty close, eh?
y = x^(4/3)
dy = (4/3)x^(1/3) dx
so, if dx = -0.1
dy = (4/3)(3)(-0.1) = -0.4
So, 26.9^(4/3) ≈ 80.6
In fact 26.9^(4/3) = 80.6002
pretty close, eh?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.