Asked by Anonymous
Calculate the kinetic energy of the photoelectron emitted by a metal (threshold energy is 1.50 x 10^-19J) exposed to light of wavelength 5.00 x 10^-7 m (the energy beyond that required to knock electron goes into electron kinetic energy).
A) -3/98 x 10^-19J
B) 3.98 x 10^-19J
C) 2.48 x 10^-19J
D) 1.50 x 10^-19J
E) 8.3141J
A) -3/98 x 10^-19J
B) 3.98 x 10^-19J
C) 2.48 x 10^-19J
D) 1.50 x 10^-19J
E) 8.3141J
Answers
Answered by
DrBob222
dE = hc/lambda = ?
KE = dE-threshold
KE = dE-threshold
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