Asked by Duane
h(x)=(x^12-2)^3
h'(x)=
h'(x)=
Answers
Answered by
Steve
let u = x^12-2. Then we have
h = u^3, so
h' = 3u^2 u'
= 3(x^12-2)^2 (12x^11)
= 36 x^11 (x^12-2)^2
h = u^3, so
h' = 3u^2 u'
= 3(x^12-2)^2 (12x^11)
= 36 x^11 (x^12-2)^2
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