Asked by Juan

Carrie attained a score of 650 on the verbal section of her SAT. The mean grade was a 500 with a standard deviation of 100. What percentage of test takers scored below and above Carrie?

Answered by PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z score. Multiply by 100.
Answered by Anonymous
k89
Answered by Anonymous
50
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