Asked by Anonymous
One isotope of holmium, 162Ho, has a half life of 22 minutes. The half-life of a second isotope, 164Ho, is 37 minutes. Starting with a sample containing equal amounts, find the ratio of the amounts of 162Ho to 164Ho after one hour. Rounded to three decimal
Answers
Answered by
Steve
after t minutes, the two isotopes have remaining amounts of
2^(-t/22) and 2^(-t/37)
So, after one hour (60 minutes), the ratio of 162Ho/164Ho is just
2^(-60/22) / 2^(-60/37)
= 2^(-60/22 + 60/37)
= 2^(-450/407)
= 2^-1.10565
= 0.465
2^(-t/22) and 2^(-t/37)
So, after one hour (60 minutes), the ratio of 162Ho/164Ho is just
2^(-60/22) / 2^(-60/37)
= 2^(-60/22 + 60/37)
= 2^(-450/407)
= 2^-1.10565
= 0.465
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