we have initial velocity (Vx,Vy)
y = Vy t - 4.9t^2
4.8Vy - 4.9*4.8^2 = 0
Vy = 23.52
x = Vx t
52 = Vx * 4.8
Vx = 10.83
So, v^2 = 10.83^2 + 23.52^2
v = 25.90
at an angle θ such that
tanθ = Vy/Vx = 23.52/10.83 = 2.17
θ = 65.28°
Now you can plug those values into your usual trajectory formulas.
A NFL punter kicks a ball and lands 52 m away and is in the air for 4.8s. Assume that the ball lands at the same level that is is kicked.
a. determine the initial velocity of the punt (magnitude and direction)
b. determine the maximum height of he punt
c. if the punter kicked the ball through the end zone toward the field goal post which is located 45 m away and is 3.2 m tall, determine if the ball traveled over or under the field goal post on its way to the ground and provide evidence to support your answer.
please help !!!
2 answers
first of all thank you so much, but is the initial velocity 23.54 or 10.83 and can you just give me the formulas of how to solve b and c especially c
1 answer