If that reaction is 1:1 (1 mol cyclohanol gives 1 mol cyclohexene and I think it does), then
mols cyclohexanol = grams/molar mass = ?
mols cyclohexene = same
g cyclohexene = mols x molar mass = ?. This yield in grams in the theoretical yield (TY) and is the answer to part b.
I think part a question is not stated properly. I assume you want percent yield. That is (24.6/TY)*100 = ?
Technically, I think the yield is the 24.6 g. If you want percent yield you should ask for percent yield. Actually, I don't know what the term w/w means except when I quote a mass percent I usually write something like 12.0% w/w meaning 12.0 mass percent.
if you used 40 g of cyclohexanol and obtained 24.6g of pure cyclohexene,
a) what is your w/w yield?
b) what is your theory yield?
Thank you !
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