Asked by Frnciois
The stopping distance d of a car after the brakes have been applied varies directly as the square of the speed r. if the car traveling 70mph cab stop in 270ft, how many feet will it take the same car to stop when it 1s traveling 50 mph
Answers
Answered by
drwls
Stopping distance = C r^2
270 = C*70^2
C = 270/70^2
At 50 mph,
stopping distance = 50^2*270/(70^2)
= (5/7)^2 * 270 ft = ?
270 = C*70^2
C = 270/70^2
At 50 mph,
stopping distance = 50^2*270/(70^2)
= (5/7)^2 * 270 ft = ?
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