Asked by John

A person is kayaking in the ocean at 5.6 m/s 75° to the horizon when he experiences a current of 3.8 m/s 45° south of west. What is the speed and direction of his kayak?
Answered by william
A cable with 24.0N of tension pulls straight up on a 1.02kg block that is initially at rest
What is the block's speed after being lifted 2.20m ? Solve this problem using work and energy.
Express your answer with the appropriate units.


Answered by Don
John, first draw a free body diagram.

then break each vectors up into x and y components

Fx = 5.6cos75 - 3.8cos45

Fy = 5.6sin75 - 3.8sin45

Direction:
tan^-1(Fy/Fx)
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