x = t^4 - 6t^2 + 9t
Take the derivative to get the velocity.
v = 4t^2 - 12t + 9
Take the derivative again to get acceleration.
a = 8t - 12
Now, let's shift to force formulas.
F = ma
If a = 0, F = 0. Therefore, the net force on the locomotive is equal to zero at the time when a = 0.
a = 0 = 8t -12
8t -12 = 0
8t = 12
t = 12/8 = 1.5 seconds
The position of a toy locomotive moving on a
straight track along the x-axis is given by the
equation
x = t4 − 6 t2 + 9 t ,
where x is in meters and t is in seconds.
The net force on the locomotive is equal to
zero when t is equal to
1 answer
1 answer