Asked by kristen
establish the identity:
cot(A-B)= cotAcotB+1/cotB-cotA
thanks for any help at all
cot(A-B)= cotAcotB+1/cotB-cotA
thanks for any help at all
Answers
Answered by
drwls
Is the final term
1/(cotB-cotA) or
(1/cotB)-cotA ??
Is the numerator term (cotA cotB +1) or 1 ?
When you write equations like that, we can't tell what you mean.
I suggest you start with the identities for cos (A-B) and sin (A-B) and take the ratio of the two.
1/(cotB-cotA) or
(1/cotB)-cotA ??
Is the numerator term (cotA cotB +1) or 1 ?
When you write equations like that, we can't tell what you mean.
I suggest you start with the identities for cos (A-B) and sin (A-B) and take the ratio of the two.
Answered by
Anonymous
cos(a+b)/sin(a+b)=
cosacosb+sinasinb/sinacosb-cosasinb
multiplying and dividing by sinasins then it becomes
cotacotb+1/cotb-cota
cosacosb+sinasinb/sinacosb-cosasinb
multiplying and dividing by sinasins then it becomes
cotacotb+1/cotb-cota
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.