Asked by Kaley
To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. It is found that she weighs 690 N when weighed in air and 36.0 N when weighed underwater. What is her average density?
Answers
Answered by
Damon
m g = 690
mg - 1000 kg/m^3 * V g = 36
1000 V g = 690 - 36 = 654 N
g = 9.8
so
V = 654/(1000 g)
rho = m/V = 690/g / .654/g = 1055 kg/m^3
just a little heavier than water (must have expelled all air from her lungs to sink like that)
mg - 1000 kg/m^3 * V g = 36
1000 V g = 690 - 36 = 654 N
g = 9.8
so
V = 654/(1000 g)
rho = m/V = 690/g / .654/g = 1055 kg/m^3
just a little heavier than water (must have expelled all air from her lungs to sink like that)
Answered by
wang Chung lee the cat killer
IDK I kill cats for a living
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