Asked by Chandler

Assuming an element's half-life is 3.6 years. How much of 2 grams of the element would remain after 10.8 years?

Answers

Answered by DrBob222
k = 0.693/t<sub>1/2</sub>
Substitute into the below equation.

ln(No/N) = kt
No = 2 g from the problem.
N = to be calculated (how much is left)
k from above.
t = 10.8 years.
Solve for N
Answered by Anonymous
.25
Answered by Anonymous
1.6

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