Asked by kim

Using the Descartes Rule of Sign count the number of sign changes of f(-x) and determine the number of negative real zeros.

1. f(x)=x^3+x^2-10x-24
My answer: A few signs due change but not enough to say they changed." 0 sign changes of f(-x), which means f(x) has 0 negative real zeros.
Answered by Steve
f(-x) = -x^3+x^2+10x-24
2 sign changes, mean either 2 or 0 negative roots

"A few" is not a very precise answer.
Answered by kim
than you again steve! I know I should have said "2" I am sorry. Thank you for correcting me. I appreciate your help.
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