Question

110 members of a sports club play atleast one of the games, football, basketball and volleyball. If 20 play football and basketball only, 15 play football and volleyball only, 26 play basketball and volleyball only, x play all the three games, 2x each play only one game, how many play basketball altogether?

Answer 1

i need answer

Answer 2

52

Answer 3

52 is the answer

Answer 4

Let the Sports Club be denoted by U,
.
F = Football
.
B = Basketball
.
V = Volleyball
.
n(U) = 110
.
n(FnBnC') = 20
.
n(FnVnB') = 15
.
n(BnVnF') = 26
.
n(FnBnV) = x
.
n(FnB'nV') = n(F'nBnV') = (F'nB'nV) = 2x
.

Note: B', F' and V' denote the complements of the various sets(clubs).
.
n(U) = n(FuBuV) + n(FuBuV)'
.
In this case, n(FuBuV)' is empty.
.
110 = 2x + 20 + x + 15 + 2x + 26 + 2x
.
110 = 61 + 7x
.
49 = 7x
.
x = 7
.
n(B) = 20 + 26 + x + 2x
.
n(B) = 20 + 26 + 3x
.
n(B) = 20 + 26 + 21
.
n(B) = 67
.
67 members play Basketball altogether.

~Darematics(07034495462)

Answer 5

67 members play basketball altogether

Answer 6

Pls how was the answer 52 gotten

Answer 7

Pls Ayodeji And Edidiong Umanah How Did U Get 52 To Be The Answer

Answer 8

How many played football and how many played volleyball. Please I need a straight answer

Answer 9

Pls how was 52 gotten

Answer 10

pls how did you get 52

Answer 11

Thank you so much
Have been trying it all day but still didn't get

Answer 12

Pls can u represent in on a venn diagram

Answer 13

How did you arrive at 52

Answer 14

Pls can u represent it in a Venn diagram