Asked by David
A small pumpkin of mass 2.22 kg is dropped from rest from a height of 2.87 m. The pumpkin rebounds from the ground to a height of 1.12 m.
a. With what speed does the pumpkin hit the ground?
b. With what speed does the pumpkin leave the ground?
c. What impulse was given to the pumpkin by the ground?
I know you use the rules of linear momentum but i just don't understand how to do this, any help please?
a. With what speed does the pumpkin hit the ground?
b. With what speed does the pumpkin leave the ground?
c. What impulse was given to the pumpkin by the ground?
I know you use the rules of linear momentum but i just don't understand how to do this, any help please?
Answers
Answered by
Damon
(1/2) m v^2 = m g h
so
v1 = -sqrt(2 g h) (coming down)
h = -2.87 coming down
going up same deal but opposite sign for v
v2 = + sqrt(2*9.8*1.12)
change in momentum = m (v2-v1)
so
v1 = -sqrt(2 g h) (coming down)
h = -2.87 coming down
going up same deal but opposite sign for v
v2 = + sqrt(2*9.8*1.12)
change in momentum = m (v2-v1)
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