Asked by Kales
A home swimming pool contains 145 m3 of water. At the beginning of the swimming season, the water must be heated from 20 to 32°C. How many joules of heat energy must be supplied?
Answers
Answered by
DrBob222
1 m^3 = 1000 L so
145 m^3 = 145,000 L = 145,000,000 mL 145,000,000 grams.
q needed = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for q in J.
145 m^3 = 145,000 L = 145,000,000 mL 145,000,000 grams.
q needed = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for q in J.
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