Question
The angles of elevation of the top of a tower as observed from the bottom and top of a building of height 6th are 60° and 45° respectively.The distance of the base of the tower from the base of the building?
Answers
Steve
If the tower has height h and is at a distance x, then
h/x = tan 60°
(h-6th)/x = tan 45°
Eliminating h, we have
x/tan 60° = x tan 45° + 6th
x(1-1/√3) = 6th
x = 6th/(1-1/√3)
whatever 6th is supposed to mean.
h/x = tan 60°
(h-6th)/x = tan 45°
Eliminating h, we have
x/tan 60° = x tan 45° + 6th
x(1-1/√3) = 6th
x = 6th/(1-1/√3)
whatever 6th is supposed to mean.