Asked by asmita
The angles of elevation of the top of a tower as observed from the bottom and top of a building of height 6th are 60° and 45° respectively.The distance of the base of the tower from the base of the building?
Answers
Answered by
Steve
If the tower has height h and is at a distance x, then
h/x = tan 60°
(h-6th)/x = tan 45°
Eliminating h, we have
x/tan 60° = x tan 45° + 6th
x(1-1/√3) = 6th
x = 6th/(1-1/√3)
whatever 6th is supposed to mean.
h/x = tan 60°
(h-6th)/x = tan 45°
Eliminating h, we have
x/tan 60° = x tan 45° + 6th
x(1-1/√3) = 6th
x = 6th/(1-1/√3)
whatever 6th is supposed to mean.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.