I think I worked this for you last night. First you need to correct the equation to
2Mg + O2 --> 2MgO
mols O2 = grams/molar mass = 16/32 = 0.5
0.5 mol O2 x (2 mol Mg/1 mol O2) = 0.5 x 2/1 = 1 mol Mg
How many moles of magnesium are needed to react with 16 g of O2?
2 MgO (s) + O2 (g) → 2 MgO (s)
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