Asked by Cherie
A manufacturer is designing an open, cube shaped box to hold a basketball. The basketball has a volume of 2304 Pi cm3.
How much cardboard is needed to create the smallest box possible using the least amount of material? DO NOT include seam overlap in the calculations.
Please help!!
How much cardboard is needed to create the smallest box possible using the least amount of material? DO NOT include seam overlap in the calculations.
Please help!!
Answers
Answered by
GanonTEK
vol of a sphere = (4/3)*pi*r^3 = 2404*pi
find r from that. The length, width and height of the box around the sphere will be the diameter of the ball. Diameter = 2r
Area of box = 6*(2r)^2 = 24r^2 cm2
(6 identical faces of area 2r*2r)
find r from that. The length, width and height of the box around the sphere will be the diameter of the ball. Diameter = 2r
Area of box = 6*(2r)^2 = 24r^2 cm2
(6 identical faces of area 2r*2r)
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