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Asked by r

A bear spies some honey and takes off from rest, accelerating at a rate of 1.9 m/s^2. If the honey is 17m away, How fast will the bear be going when he gets to the honey?
11 years ago

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Answered by Damon
17 = (1/2) 1.9 t^2
solve for t
v = 1.9 t
11 years ago
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A bear spies some honey and takes off from rest, accelerating at a rate of 1.9 m/s^2. If the honey is 17m away, How fast will the bear be going when he gets to the honey?

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