Asked by r
A bear spies some honey and takes off from rest, accelerating at a rate of 1.9 m/s^2. If the honey is 17m away, How fast will the bear be going when he gets to the honey?
Answers
Answered by
Damon
17 = (1/2) 1.9 t^2
solve for t
v = 1.9 t
solve for t
v = 1.9 t
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