Sanjay's air boat starts from rest and accelerates at 4.6 m/s2 for a distance of 219 meters. How fast is it moving at the end of the 219 meters?

1 answer

d = Vo t + (1/2) a t^2

219 = 0 + 2.3 t^2
solve for t

v = Vo + a t
v = 0 + 4.6 t