Asked by Kales
When 2.25 g of sodium hydroxide (NaOH) was dissolved in 150.00 g of water a value of 11.00oC was obtained for ΔT.
1. Calculate the molarity of the sodium hydroxide solution.
2. Calculate the value (calories) for the heat of solution of 2.25 g of NaOH.
3. Calculate the number of calories that would be produced if one mole of sodium hydroxide was dissolved. (ΔHsolnNaOH)
1. Calculate the molarity of the sodium hydroxide solution.
2. Calculate the value (calories) for the heat of solution of 2.25 g of NaOH.
3. Calculate the number of calories that would be produced if one mole of sodium hydroxide was dissolved. (ΔHsolnNaOH)
Answers
Answered by
DrBob222
1. mols NaOH = grams/molar mass
Then M = mols/L solution. I suppose you are supposed to take the density of H2O as 1.0 g/mL which makes 150.00g H2O= 150 mL.
2. q = mass H2O x specific heat H2O x delta T
3. delta H rxn = q/2.25 give you per gram.
That x molar mass NaOH gives delta H rxn per mole.
Then M = mols/L solution. I suppose you are supposed to take the density of H2O as 1.0 g/mL which makes 150.00g H2O= 150 mL.
2. q = mass H2O x specific heat H2O x delta T
3. delta H rxn = q/2.25 give you per gram.
That x molar mass NaOH gives delta H rxn per mole.
Answered by
Kales
The process for #2 didn't work. I got found the answer to be -1590 but I'm not sure how to get that answer
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