Question
What mass KCl is needed to precipitate AgCl from 15.0 mL of .200 M AgNO3
Answers
DrBob222
AgNO3 + KCl ==> AgCl + KNO3
mols AgNO3 = M x L = ?
mols KCl needed = mols AgNO3 because of the coefficients in the balanced equation.
mols KCl = grams KCl/molar mass KCl. You know molar mass and mols KCl, solve for grams.
mols AgNO3 = M x L = ?
mols KCl needed = mols AgNO3 because of the coefficients in the balanced equation.
mols KCl = grams KCl/molar mass KCl. You know molar mass and mols KCl, solve for grams.