A 80kg crate Is pushed 35m across the floor with a force of 500n the coefficient of kinetic friction is 0.25 how much for is done on the crate by pushing it"

Answer 1

Fc = m*g = 80kg * 9.8N/kg = 784 N. = Force of crate.

Fn = Fc = 784 N. = Normal.

Fk = u*Fn = 0.25 * 784 = 196 N. = Force
of kinetic friction.

Work = (Fap-Fk))* d = (500-196) * 35 =
10,640 J.