Asked by TeeKay
Find cos2A when cosA = -3/5 and π/2<A<π.
A) -24/25
B) -7/25
C) 7/24
D) 24/7
A) -24/25
B) -7/25
C) 7/24
D) 24/7
Answers
Answered by
Steve
just use the double-angle formula:
cos2A = 2cos^2 A - 1
cos2A = 2cos^2 A - 1
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