1. Determine the limiting reagent which will be either HCl or Ba(OH)2. It looks like HCl but you should confirm that before going further.
q = 118 kJ x (g HCl/2*molar mass HCl)
2. Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Substitute and solve for Tf.
Consider the following reaction.
2 HCl(aq) + Ba(OH)2(aq) BaCl2(aq) + 2 H2O(l) ΔH = -118 kJ
Calculate the heat when 114.8 mL of 0.500 M HCl is mixed with 300.0 mL of 0.400 M Ba(OH)2. Assuming that the temperature of both solutions was initially 25.0°C and that the final mixture has a mass of 414.8 g and a specific heat capacity of 4.18 J/°C·g, calculate the final temperature of the mixture.
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