Consider a rod plus disc system. The rod has a total length L =1.30 m, while the disc has a radius of R = L/2. The pivot is at P where the distance between P and the end of the rod is L/4. Point O is at the center of the disc, and the distance between O and P is 0.975 m. The rod has a mass of m1= 3.40 kg and the mass of the disc is M2= 10.20 kg. Assume that the disc and rod have uniform mass distributions.

Question

Consider a rod plus disc system. The rod has a total length L =1.30 m, while the disc has a radius of R = L/2. The pivot is at P where the distance between P and the end of the rod is L/4. Point O is at the center of the disc, and the distance between O and P is 0.975 m. The rod has a mass of m1= 3.40 kg and the mass of the disc is M2= 10.20 kg. Assume that the disc and rod have uniform mass distributions.
a) what is the center of mass of the rod and disc relative to point P?
b) Find the moment of inertia of the rod, in units of kgm2, as the pendulum freely rotates about the point P. 
c) Find the moment of inertia of the disk, in units of kgm2, as the pendulum freely rotates about the point P. 
d) Find the moment of inertia of the pendulum, in units of kgm2, as it freely rotates about the point P.

I have found that the vertical coordinate of the rod relative to P is -0.325 if that helps.