Question
If the first dice yields an even number, what is the probability that the sum of the two dices will be equal to 12?
1st Die
P(even) = 3/6 = 0.50
P(6|even) = 1/3 = 0.333
2nd Die
P(6) = 1/6 = .1667
So P(12) = 0.5*0.33*0.1667 ?
1st Die
P(even) = 3/6 = 0.50
P(6|even) = 1/3 = 0.333
2nd Die
P(6) = 1/6 = .1667
So P(12) = 0.5*0.33*0.1667 ?