Question

how to solve one pulley is 7 cm larger in diameter than a second pulley. the larger pulley turns at 80 rpm, and the smaller pulley turns at 136 rpm. what is the diameter of each pulley
let the diameter of the small pulley be d
let the diameter of the larger pulley be d+7

belt distance covered by smaller pulley in one minute
= 136(πd)
= 136πd
by the larger pulley
= 80(π)(d+7)

so 136πd = 80π(d+7)
divide out the π
136d = 80d + 560
etc

you state the conclusion

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