A drum (see Figure 10.2) has a radius of 0.40 m and a moment of inertia of 2.3 kg ∙ m2. The frictional torque of the drum axle is A 14 m length of rope is wound around the rim. The drum is initially at rest. A constant force is applied to the free end of the rope until the rope is completely unwound and slips off. At that instant, the angular velocity of the drum is The drum then decelerates and comes to a halt. In this situation, the constant force applied to the rope is closest to:
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Not knowing that frictional torque, I am at a loss. Please proof read question.
In the end
torque = F*.4 - friction torque = I d omega/dt
torque = F*.4 - friction torque = I d omega/dt
1 answer