Asked by Logan
a 191 g piece of copper is heated to 100 C in a boiling water bath and then dropped into a beaker containing 755 g of water (density =1.00 g/cm3) at 4.0 C. What is the final temperature of the copper and water after thermal equilibrium is reached? (Scu=0.385 J/g•K)
Answers
Answered by
DrBob222
heat lost by Cu + heat gained by water = 0
(mass Cu x specific heat Cu x (Tfinal-Tinitial) + (mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Substitute the numbers and solve for Tf.
(mass Cu x specific heat Cu x (Tfinal-Tinitial) + (mass H2O x specific heat H2O x (Tfinal-Tinitial) = 0
Substitute the numbers and solve for Tf.
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