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How far apart should two protons be if the electrical force of repulsion is equal to the weight (attraction to the Earth) of on...Asked by Anonymous
How far apart should two protons be if the electrical force of repulsion is equal to the weight (attraction to the earth) of one of the protons? (
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The force between to protons is kq^2/r^2 (where k = 1/(4*pi*epislon_0))
This force equals mg, where m is the proton mass. So, you have
kq^2/r^2 = mg --> r^2 = kq^2/mg ---> r = q*sqrt(k/mg) ~ 11.9 cm
This force equals mg, where m is the proton mass. So, you have
kq^2/r^2 = mg --> r^2 = kq^2/mg ---> r = q*sqrt(k/mg) ~ 11.9 cm
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