Asked by Anonymous
The diameter of a human pupil in millimetres is given by
D= (2 + 4x^-0.3) / (1 + x^-0.3)
where x is the luminance measured in candelas per square metre. Using this function,what is the diameter of the pupil when there is no light? What happens to the diameter of the pupil as it gets brighter and brighter?
D= (2 + 4x^-0.3) / (1 + x^-0.3)
where x is the luminance measured in candelas per square metre. Using this function,what is the diameter of the pupil when there is no light? What happens to the diameter of the pupil as it gets brighter and brighter?
Answers
Answered by
Steve
try multiplying top and bottom by x^0.3
(2x^0.3+4)/(x^0.3+1)
Now you have a nice simple limit of 4/1
As x gets big, x^-0.3 vanishes, and the limit is 2/1
(2x^0.3+4)/(x^0.3+1)
Now you have a nice simple limit of 4/1
As x gets big, x^-0.3 vanishes, and the limit is 2/1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.