Asked by Molly

Suppose sinA = 12/13 with 90º≤A≤180º. Suppose also that sinB = -7/25 with -90º≤B≤0º. Find cos(A - B).
Answered by Steve
A is in QII, so cosA = -5/13
B is in QIV, so cosB = 24/25

Now, you have

cos(A-B) = cosAcosB + sinAsinB
...
Answered by Dumb
What kinda answer is that Steve
EH?



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