If the mean rate of arrival in a restaurant is 10 customers per hour, what is the probability of having 4 customers arriving in any hour?
2 answers
What is your measure of variability?
I have answer this question as follow:
P(C)=(ac*e-a)/c!=(104*e-10)/4!=
(10000*e-10)/24=(10000*2.71828-10)/24= (10000*4.5406)/24=0.45406/24=0.0185
Is it correct?
P(C)=(ac*e-a)/c!=(104*e-10)/4!=
(10000*e-10)/24=(10000*2.71828-10)/24= (10000*4.5406)/24=0.45406/24=0.0185
Is it correct?