Asked by Bob
How fast is the tire traveling in mph if it does 2 rotations in 2 seconds with a diameter of 27 inches for the tire?
Answers
Answered by
Reiny
if it does 2 rotations in 2 seconds, then it does
1 rotation in 1 second
or 2π(13.5) inches per second
= 2π(13.5)/12 ft /sec
=7.06858.... ft/s (I stored in in my calculator memory for accuracy)
= (7.06858...)/5280 miles / (1/3600) hr
= appr 4.82 mph
1 rotation in 1 second
or 2π(13.5) inches per second
= 2π(13.5)/12 ft /sec
=7.06858.... ft/s (I stored in in my calculator memory for accuracy)
= (7.06858...)/5280 miles / (1/3600) hr
= appr 4.82 mph
Answered by
Don
circumference of a circle:
C=2*pi*r
where r=radius=27/2=13.5ft
pi=3.14
C=84.78
It's making 2 rotations every 2 seconds or in other words, 1 rotation every 1 second.
note its asking for mph:
1hour=3600
12inch=1foot
1mile=5280
Formula to solve this:
(n*C*3600)/(12*5280)
where n= number of rotations per sec
C=circumferene, and everything else is conversions to get to mph
(1*84.78*3600)/(12*5280) = 4.816mph
Someone check the work and method just to be sure.
C=2*pi*r
where r=radius=27/2=13.5ft
pi=3.14
C=84.78
It's making 2 rotations every 2 seconds or in other words, 1 rotation every 1 second.
note its asking for mph:
1hour=3600
12inch=1foot
1mile=5280
Formula to solve this:
(n*C*3600)/(12*5280)
where n= number of rotations per sec
C=circumferene, and everything else is conversions to get to mph
(1*84.78*3600)/(12*5280) = 4.816mph
Someone check the work and method just to be sure.
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